If force (F), area
A
and density 
B
C
D
are taken as the fundamental units, the dimensional representation of Youngs modulus will be -
Text Solution
Verified by ExpertsThe correct answer is:
C
[Y] = [F a A b D c ]
[ML –1 T –2 ] = [(MLT –2 ) a (L 2 ) b (ML –3 ) c ]
equating power of M, L and T
1 = a + c, –1 = a + 2b – 3c
–2 = – 2a a = 1, c = 0
b = – 1
[Y] = F A –1 D 0
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